## Base and height on one triangle is 6 and 3 base of another triangle is 12 and 1 their ratio is 9:4

Question

Base and height on one triangle is 6 and 3 base of another triangle is 12 and 1 their ratio is 9:4

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1 month 2021-10-26T12:02:25+00:00 2 Answers 0 views 0

1. Step-by-step explanation:

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

\begin{gathered}= \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\\end{gathered}

=

areaofpqr

areaofabc

=

2

1

×pm×qr

2

1

×ae×bc

=

2

1

×6×10

2

1

×5×9

=

4

3

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

Hope it helps

The required ratio is 1 : 2.

Step-by-step explanation:

Let,

The triangle having 6 units as base and 3 units as height is ∆ ABC

And,the triangle having 12 units as base and 1 units as height is ∆ PQR

___________________

Now,

Area of ∆ ABC = (base × height)/2

Area of ∆ ABC =(6×3)/2

Area of ∆ ABC = 18/2 = 9 unit²

———————–

Area of ∆ PQR = (9×4)/2

Area of ∆ PQR = 9×2=18 unit²

——————–

Ratio = 9 : 18

Ratio = 1:2

HOPE THIS HELPS