Base and height on one triangle is 6 and 3 base of another triangle is 12 and 1 their ratio is 9:4

Question

Base and height on one triangle is 6 and 3 base of another triangle is 12 and 1 their ratio is 9:4

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Amelia 1 month 2021-10-26T12:02:25+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-26T12:03:46+00:00

    Step-by-step explanation:

    ♦ Given :- Let The triangle be ∆ABC and ∆PQR.

    In ∆ABC,

    Base of ∆ABC is BC = 9cm

    Altitude of ∆ABC is AE = 5cm

    In ∆PQR,

    Base is QR = 10cm

    Altitude is PM = 6cm

    ♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

    ♦ Solution :-

    \begin{gathered}= \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\\end{gathered}

    =

    areaofpqr

    areaofabc

    =

    2

    1

    ×pm×qr

    2

    1

    ×ae×bc

    =

    2

    1

    ×6×10

    2

    1

    ×5×9

    =

    4

    3

    Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

    Hope it helps

    0
    2021-10-26T12:03:51+00:00

    Answer:


    The required ratio is 1 : 2.


    Step-by-step explanation:


    Let,

    The triangle having 6 units as base and 3 units as height is ∆ ABC

    And,the triangle having 12 units as base and 1 units as height is ∆ PQR

    ___________________

    Now,

    Area of ∆ ABC = (base × height)/2

    Area of ∆ ABC =(6×3)/2

    Area of ∆ ABC = 18/2 = 9 unit²

    ———————–

    Area of ∆ PQR = (9×4)/2

    Area of ∆ PQR = 9×2=18 unit²

    ——————–

    Ratio = 9 : 18

     

    Ratio = 1:2

    HOPE THIS HELPS

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