## Bus A and Bus B leave the bus depot at 7 am. Bus A takes 25 minutes to complete its route once and bus B takes 40 minutes to complete

Question

Bus A and Bus B leave the bus depot at 7 am.

Bus A takes 25 minutes to complete its route once and bus B takes 40 minutes to complete its route once.

If both buses continue to repeat their route, at what time will they be back at the bus depot together?

in progress
0

Math
3 weeks
2021-10-05T05:24:40+00:00
2021-10-05T05:24:40+00:00 2 Answers
0 views
0
## Answers ( )

Given : Bus A and Bus B leave the bus depot at 7 am.

Bus A takes 25 minutes to complete its route once and bus B takes 40 minutes to complete its route once.

To find :at what time will they be back at the bus depot together?Solution:Bus A takes 25 minutes to complete its route once

Bus B takes 40 minutes to complete its route

To find time when they will be back at the bus depot together we need to find LCM of 25 & 40 Minutes

25 = 5 * 5

40 = 2 * 2 * 2 * 5

LCM = 2 * 2 * 2 * 5 * 5

= 200

After 200 minutes Buses will be back at the bus depot together

200 minutes = 3 hr 20 Minutes

7 : AM + 3 hr 20 Minutes

= 10 : 20 AM

At 10 : 20 AM Buses be back at the bus depot togetherLearn More:

find the lcm of 90 and 120 – Brainly.in

https://brainly.in/question/7842410

Find LCM and HCF of the following pairs of integers and verify that …

https://brainly.in/question/17387230

Step-by-step explanation:Bus A and Bus B leave the bus depot together at 7 am.

The time taken by both the buses to come back at the bus depot together will be equal to the LCM

(largest common multiple) of the time taken by Bus A and Bus B.

The prime factorization of 25 and 40 are

\begin{gathered}25=5\times5,\\

\\40=2\times2\times2\times5.\end{gathered

}25=5×5,40=2×2×2×5.

So,

LCM(25,40)=2\times2\times2\times5\times5=200.LCM(25,40)=2×2×2×5×5=200.

200 minutes = 3 hours 20 minutes.

Therefore, the buses will come back at the bus depot at

7~\textup{AM}+3~\textup{hours }20~\textup{minutes}=10:20~\textup{AM}.7 AM+3 hours 20 minutes=10:20 AM.

Thus, bus A and bus B both come back at 10:20 AM.