By How much must be the sum of 6p^2q-4pq+2q^2p and 5q^2p + 5pq be increased to get 8p^2q+5pq÷7q^2p​

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By How much must be the sum of 6p^2q-4pq+2q^2p and 5q^2p + 5pq be increased to get 8p^2q+5pq÷7q^2p​

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Madeline 1 month 2021-08-20T17:56:23+00:00 1 Answer 0 views 0

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    2021-08-20T17:57:27+00:00

    Answer:

    sum \: of \:  {6p}^{2q}  - 4pq +  {2q}^{2p}   \:  and \:  {5q}^{2p}  + 5pq \: is

    {6p}^{2q}  - 4pq +  {2q}^{2p}   +  ({5q}^{2p}  + 5pq)

     {6p}^{2q}  - 4pq +  {2q}^{2p}  +  {5q}^{2p}  + 5pq

     {6p}^{2q}  +  {5q}^{2p}  +  {2q}^{2p}  - 4pq + 5pq

    {6p}^{2q} +  {7q}^{2p}  + pq

    {6p}^{2q} +  {7q}^{2p}  + pq + (x) =   \frac{{8p}^{2q}  + 5pq}{ {7q}^{2p} }

    x =\frac{{8p}^{2q}  + 5pq}{ {7q}^{2p} }  - ({6p}^{2q} +  {7q}^{2p}  + pq)

    x = \frac{{8p}^{2q}  + 5pq}{ {7q}^{2p} } - {6p}^{2q}  -   {7q}^{2p}    - pq

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