calculate the number of moles present in 9g of ethane​

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calculate the number of moles present in 9g of ethane​

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Faith 2 weeks 2021-10-07T12:57:03+00:00 2 Answers 0 views 0

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    0
    2021-10-07T12:58:24+00:00

    Answer:

    0.3

    Step-by-step explanation:

    ethane – C2H6

    Its molecular mass = 12*2 + 6*1  = 30

    according to mole concept;

    molecular mass of a compound  ——- 1 mole of that compound    

              that is , 30 g ethane——1 mole ethane

        therefore , 9 g ethane——- (1*9)  / 30

                                                = 9/30

                                                 = 0.3

    hope it help u                                                                                          

    0
    2021-10-07T12:58:42+00:00

    Answer:

    Molar mass of ethane is 2(molar mass of carbon) + 6(molar mass of hydrogen). Mm = 2(12) +6(1) = 30 g/gmol. Moles of ethane in 9 g is equal to 9g/(30 g/gmol)=. 3 gmol C2H6.

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