consecutive numbers of an arithmetic sequence is k+1 ,2k+1, 13 . Find the value of k​

Question

consecutive numbers of an arithmetic sequence is k+1 ,2k+1, 13 . Find the value of k​

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Josephine 2 weeks 2021-09-04T18:48:58+00:00 2 Answers 0 views 0

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    2021-09-04T18:50:26+00:00

    Answer:

    k=4 is the answer

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    0
    2021-09-04T18:50:35+00:00

    Answer:

    k = 4

    Step-by-step explanation:

    13 – (2k + 1) = (2k + 1) – (k + 1)

    13 – 2k – 1 = 2k +1 – k – 1

    12 – 2k = k

    3k = 12

    k = 12/3

    k = 4

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