An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.3) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.

An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.3) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.4) Join A to B and C.

## Answers ( )

Answer:An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.3) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.An equilateral triangle of side 5.5 cm has to be constructed. We know that all sides of an equilateral triangle are of equal length. Therefore, a triangle ABC has to be constructed with AB = BC = CA = 5.5 cm.The steps of construction are as follows.1) Draw a line segment BC of length 5.5 cm.2) Taking point B as centre, draw an arc of 5.5 cm radius.3) Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.4) Join A to B and C.Step-by-step explanation:hop its help you my dear friend

draw a line segment BC of length 5.5 cmDraw a line segment BC of length 5.5 cm.

Taking point B as centre, draw an arc of 5.5 cm radius.

Taking point C as centre, draw an arc of 5.5 cm radius to meet the previous arc at point A.

Join A to B and C.