cos 100° +sin 20° +cos 10° sin 50 sin 350 sin 50 = – cos ec50° cos ec35° cos ec5° + (A) 5 (B) 3 (C) 2 (D)

Question

cos 100° +sin 20° +cos 10°
sin 50 sin 350 sin 50
=
– cos ec50° cos ec35° cos ec5° +
(A) 5
(B) 3
(C) 2
(D) 1​

in progress 0
Jade 8 months 2021-09-23T10:00:36+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-23T10:02:12+00:00

    cos ec50° cos ec35° cos ec5° +

    (A) 5

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )