cuboidal box is to as 12.5 CM Long. 10cm and 8 CM high. 1 which box has the greater lateral surface and by how much?

Question

cuboidal box is to as 12.5 CM Long. 10cm
and 8 CM high.
1 which box has the greater lateral surface
and by how much?

Which box has the smaller total surface area and by how much?

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Claire 1 month 2021-09-14T23:56:17+00:00 2 Answers 0 views 0

Answers ( )

  1. Answer:

    A cubical box has each edge 10 cm and another cuboidal box is 12.5 cm long, 10 cmwide and 8 cm high. (i) Which box has the greater lateral surface area and by how much?(ii) Which box has the smaller total surface area and by how much? difference=600-592=8cm2.

    Step-by-step explanation:

    hope it will be helpful and please mark as brainlist and follow please

    0
    2021-09-14T23:58:16+00:00

    Question ::-

    A cubical box has each edge 10 cm and another cuboidal box is 12.5 cm long, 10 cm wide and 8 cm high.

    (i) Which box has the greater lateral surface area and by how much?

    (ii) Which box has the smaller total surface area and by how much?

    Given ::-

    • Length of cuboid = 12.5cm
    • Height of cuboid = 8cm

    To find ::-

    • Which box has the greater lateral surface area and by how much?
    • Which box has the smaller total surface area and by how much?

    Solution ::-

    For the cubical box with edge

    (a) = 10 cm

    Lateral surface area

    = {4a}^{2}

    = 4 x {10}^{2} {cm}^{2}

    = 400 {cm}^{2}

    _______

    Total surface area

    = {6a}^{2}

    = 6 x {10}^{2} {cm}^{2}

    = 600 {cm}^{2}

    ________

    For the cuboidal box with dimensions,

    • Length (l) = 12.5 cm,
    • Breadth (b) = 10 cm,
    • Height (h) = 8 cm

    ∴ Lateral surface area

    = 2[l + b] x h

    = 2[12.5 + 10] x 8 {cm}^{2}

    = 360 {cm}^{2}

    __________

    Total surface area

    = 2[lb + bh + hl]

    = 2[(12.5 x 10) + (10 x 8) + (8 x 12.5)] {cm}^{2}

    = 2[125 + 80 + 100] {cm}^{2}

    = 2[305] {cm}^{2}

    = 610 {cm}^{2}

    ___________

    (i) A cubical box has the greater lateral surface area by ::-

    (400 – 360) {cm}^{2}

    = 40 {cm}^{2}

    (ii) Total surface area of a cubical box is smaller than the cuboidal box by ::-

    (610 – 600) {cm}^{2}

    = 10 {cm}^{2}

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