d/dx(cos(x)^1/2)^1/2=? please don’t give irrevealeant answers ​

Question

d/dx(cos(x)^1/2)^1/2=? please don’t give irrevealeant answers ​

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Rose 2 weeks 2021-10-08T05:46:00+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-08T05:47:19+00:00

     y = cos { - }^{1} (2 { x}^{2}  - 1)z = cos { - }^{1} x

     \frac{dy}{dz}  =  \frac{dy \div dx}{dz \div dx}

    y = cos { - }^{1} (2 {x}^{2}  - 1)

    *** QuickLaTeX cannot compile formula:
     \frac{dy}{dx}  =  \frac{ - 1}{ \sqrt{1 - 2 {x}^{2}  - 1) = (4x - 0)
    
    *** Error message:
    File ended while scanning use of \frac .
    Emergency stop.
    
    

    solve this equation

    then answer is 2

    hope it helps you

    0
    2021-10-08T05:47:51+00:00

    Answer:

    d \: cos \:  \alpha  + d \sin( \beta )  +  log( \gamma )  =  \sqrt{5}

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