differentiate sin^3x+cos^3x with respect to tan^4x+cot^6x​

Question

differentiate sin^3x+cos^3x with respect to tan^4x+cot^6x​

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Mackenzie 1 month 2021-08-19T08:44:27+00:00 1 Answer 0 views 0

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    2021-08-19T08:45:40+00:00

    Answer:

    if bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isoscelesif bisector AE of exterior vertical angle DAE of triangle abc be parallel to base BC prove that tringe is isosceles

    20. \cos( \cot( \cos( \cos(e \beta  \beta  \beta  log_{ \beta  log_{ log_{gssxx \: z \: }(?) }(?) }(?) ) ) ) )  \times \frac{?}{?}  \times \frac{?}{?}

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18:9+8+9*3-7:3-1*13 = ? ( )