Exercise – 6.2 1. Find the square of the following numbers by using distributive property. (i) 32 (ii) 35 (iii) 86 (iv) 93

Question

Exercise – 6.2
1. Find the square of the following numbers
by using distributive property.
(i) 32 (ii) 35 (iii) 86 (iv) 93
(v) 71 (vi) 46
2. Write a Pythagorean triplet whose one
member is.
(i) 6 (ii) 14 (iii) 16 (iv) 18

*PLEASE USE DISTRIBUTIVE PROPERTY IN THE 1 QUESTION WITH EXPLANATION*

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Faith 3 weeks 2021-11-06T10:15:18+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-06T10:16:46+00:00

    Hey buddy here is your answer

    Step-by-step explanation:

    Q1) I) 32^2=(30+2)^2 (Distributive)

    using (a+b) ^2= a^2 + b^2 + 2ab

    a=30, b= 2

    30^2+ 2^2 + 2*30*2

    =900+4+120

    = 1024

    Q1) ii) 35^2=(30+5)^2 (Distributive)

    using (a+b) ^2= a^2 + b^2 + 2ab

    a=30, b= 5

    30^2+ 5^2 + 2*30*5

    900+25+300

    1225

    Q1) iii) 86^2= (80+6)^2 (Distributive)

    using (a+b) ^2= a^2 + b^2 + 2ab

    (80+6)^2= 80^2 + 6^2 +2*80*6

    6400+36+960

    7496

    similarly other parts

    Q2 Pythagorean triplets are 2m, m^2+1, m^2-1

    i) lets take 2m=6

    m=3

    m^2+1= 3^2+1= 9+1= 10

    m^2-1= 3^2-1= 9-1= 8

    the triplet is 6,10,8

    ii) let’s take 2m = 14

    m= 7

    m^2+1= 7^2+1=49+1= 50

    m^2-1= 7^2-1= 49-1= 48

    the triplet is 14,50,48

    iii) let’s take 2m = 16

    m= 8

    m^2+1= 8^2+1=64+1= 65

    m^2-1= 8^2-1= 64-1= 63

    the triplet is 16,63,65

    iv) let’s take 2m = 18

    m= 9

    m^2+1= 9^2+1= 81+1= 82

    m^2-1= 8^2-1= 81-1= 80

    the triplet is 18,82,80

    I hope my answer was useful, encourage me to give such answers by marking my answer as brainliest...

    Thank you

    your Friend

    Demon 445

    0
    2021-11-06T10:17:12+00:00

    Answer:

    I) 32= (30+2)²

    =(30)²+2(30)(2)+2²

    =900+120+4

    hope it’s helps you

    plz mark me as brainlist

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