Evaluate: 1 /(√11−2√30 )+ 1 /(√7−2√10 )+ 1 /(√8−4√3)​

Question

Evaluate: 1
/(√11−2√30
)+
1
/(√7−2√10
)+
1
/(√8−4√3)​

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Reagan 4 weeks 2021-08-16T13:22:59+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-16T13:24:25+00:00

    Consider

    ConsiderShaded

    ConsiderShadedVerification of En =

    ConsiderShadedVerification of En =Squared

    ConsiderShadedVerification of En =Squaredpaper area

    ConsiderShadedVerification of En =Squaredpaper arean

    ConsiderShadedVerification of En =Squaredpaper areanarea

    ConsiderShadedVerification of En =Squaredpaper areanarea10

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 11

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 10

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σ

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σn =

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σn == 55

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σn == 552

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σn == 552n =

    ConsiderShadedVerification of En =Squaredpaper areanarea1010 x 112n = 1010 x 11 cm(10 x 11) cm = 55 cm?Σn == 552n =n =

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