factorise the polynomial x^3-4x^2-7x+10 using factor thearom ​

Question

factorise the polynomial x^3-4x^2-7x+10 using factor thearom ​

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Harper 1 month 2021-08-17T04:27:09+00:00 1 Answer 0 views 0

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    2021-08-17T04:28:53+00:00

    Answer:

    1. let x = 1, putting(x-1) in equation

    (1)³-4(1)²-7(1)+10=0

    1-4-7+10=11 – 11 =0

    hence (x-1) is a factor,

    now, divide ➗ it, by dividing we get x² – 3x – 10

    now by splitting it, we get

    x²- 5x + 2x +10

    x(x-5)-2(x-5)

    (x-2)(x-5)(x-1) are the factors

    Step-by-step explanation:

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