find all pairs of consecoutine odd poritive integers. Both of which are smaller than 10. Such that their sum is more than 11.​

Question

find all pairs of consecoutine odd poritive
integers. Both of which are smaller than
10. Such that their sum is more than 11.​

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Camila 4 weeks 2021-08-16T17:15:46+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-16T17:16:57+00:00

    Step-by-step explanation:

    Find all pairs of consecutive odd positive integers both of

    which are smaller than 10 such that their sum is more than 11.

    Let the smaller odd positive integer be x

    Since the larger integer is consecutive odd,

    Given,

    Both integers are smaller than 10,

    i.e. x < 10

    &

    X + 2 < 10

    x < 10-2

    X<8

    Sum of the two integers is more

    than 11.

    😡 + (x + 2) > 11

    2x + 2 > 11

    2x > 11 – 2

    2x > 9

    X> X >- 9 2

    X> 4.5

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