find all the zeros of x⁴-6x³+6x²+6x-7 its two factor are 3+✓2,3-✓​

Question

find all the zeros of x⁴-6x³+6x²+6x-7 its two factor are 3+✓2,3-✓​

in progress 0
Iris 1 month 2021-08-18T10:48:00+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-18T10:49:26+00:00

    -√1,√1

    Step-by-step explanation:

    let p(x)=x^4-6x^3+6x^2+6x-7

    and 3+√2,3-√2are zeroes of p(x)

    p(x)=x-3-√2),(x-3+√2)

    x^2-6x+7

    now,

    divide p(x) by x^2-6x+7

    =x^2-1

    on factorising x^2-1 ans will be

    (x-√1),(x+√1)

    x=√1,x=-√1

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )