Find dy/dx, if y=sin⁻¹ – sin⁻¹√1-x² , 0 < x < 1

Question

Find dy/dx, if y=sin⁻¹ – sin⁻¹√1-x² , 0 < x < 1

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Adeline 2 months 2021-10-04T20:31:57+00:00 1 Answer 0 views 0

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    2021-10-04T20:33:04+00:00

    Answer:

    Hola‼.......

    y=sin^-1(x)+sin^-1√(1-x^2).

    Let sin^-1(x)=A. , then x= sinA

    y= A+ sin^-1√(1-sin^2 A)

    y= A + sin^-1(cosA).

    or. y=A+sin^-1{sin(π/2-A)}.

    or. y = A +π/2 -A

    or. y= π/2.

    So, dy/dx = 0.

    Hope it’s helpful.......

    Dont copy my answer.

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