Angle between tangent drawn from the point P(1, – 1) to the circle x2 + y2 + 8x + 6y = 0 is Question Angle between tangent drawn from the point P(1, – 1) to the circle x2 + y2 + 8x + 6y = 0 is in progress 0 Math Ariana 4 weeks 2021-09-22T21:59:51+00:00 2021-09-22T21:59:51+00:00 1 Answer 0 views 0

## Answers ( )

Given :point P(1, – 1) and circle x2 + y2 + 8x + 6y = 0 isTo find :Angle between tangent drawn from the point P(1, – 1)Solution:x² + y² + 8x + 6y = 0

=> (x + 4)² – 16 + (y + 3)² – 9 = 0

=> (x + 4)² + (y + 3)² = 25

=> (x + 4)² + (y + 3)² = 5²

=> Center = – 4 , – 3

Radius = 5

Distance Between P (1 , – 1) & center (-4 ,3 )

= √(-4 – 1)² + (3 -(-1))²

= √25 + 16

= √41

2x is the angle between tangent drawn from the point P(1, – 1) to the circle x²² + y² + 8x + 6y = 0 is

Sin x = 5/√41

x =Sin⁻¹(5/√41)

=> x = 51.34°

=> 2x = 102.68°

Angle between tangent drawn from the point P(1, – 1) to the circle x² + y² + 8x + 6y = 0 is 102.68°

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