find equation of tangent and normal to hyperbole x^2/a^2 -y^2/b^2=1 at ( x°y°)​

Question

find equation of tangent and normal to hyperbole x^2/a^2 -y^2/b^2=1 at ( x°y°)​

in progress 0
Elliana 1 month 2021-08-14T20:29:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-14T20:30:58+00:00

    Answer:

    Rectangular hyperbola is a hyperbola for which the asymptotes are perpendicular, also called an equilateral hyperbola or right hyperbola.This occurs when the si-major and semi-minor axes are equal.

    So, a=b

    Since the eccentricity of the hyperbola is given by:

    e=( (a^2 + b^2)^(1/2) ) / a

    => e=(( 2*a^2 ) ^ (1/2) ) / a

    =>e = √2a / a

    Hence, e= √2.

    0
    2021-08-14T20:31:00+00:00

    Answer:

    ÷=¼½¾ flush adj spp do so so all all do to quo eel

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )