Find the base of an isoscles triangle whose area is 60cm sq. And the length of one of its equal side is 13 cm. Using formula of isoscles tri

Question

Find the base of an isoscles triangle whose area is 60cm sq. And the length of one of its equal side is 13 cm. Using formula of isoscles triangle i. e. b/4√4a^2-b^2

in progress 0
Clara 6 days 2021-09-07T07:05:13+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-09-07T07:06:17+00:00

    Answer:

    24cm

    Step-by-step explanation:

    60 = b/4 * √ [4(13)^2 – b^2]

    240 = b √(676 – b^2)

    57600/b^2 = 676 – b^2

    b^4 – 676b^2 + 57600 = 0

    let’s assume b^2 = x

    x^2 – 676x + 57600 = 0

    x = 576 , -200 . neglect – 200 as length can’t be taken as- ve .so x = 576

    b^2 = 576 => b = 24 cm

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )