6 = 2 ⋅ 3, 24 = 2³ ⋅ 3. Now, the least common multiple of 6 and some number n needs to yield a prime factorization of 2³ ⋅ 3. … So, in this case, we need n to have 3 factors of 2 and up to 1 factor of 3. This implies that there are 2 such integers n that will work.

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Answer:6 = 2 ⋅ 3, 24 = 2³ ⋅ 3. Now, the least common multiple of 6 and some number n needs to yield a prime factorization of 2³ ⋅ 3. … So, in this case, we need n to have 3 factors of 2 and up to 1 factor of 3. This implies that there are 2 such integers n that will work.

Step-by-step explanation: thanks for free pointsAnswer:I don’t know please sorry