find the equation of the straight line whose x intercept is 5 and y intercept is 4​

Question

find the equation of the straight line whose x intercept is 5 and y intercept is 4​

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Ella 1 month 2021-08-13T12:04:01+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T12:05:27+00:00

    Answer:

    4x+5y-20 =0

    Step-by-step explanation:

    process 1:

    x intercept is 5 ,  the point is (5,0)

    y intercept is 4​ , the point is (0,4)

    the equation will be \frac{x-0}{y-4}=\frac{5-0}{0-4}

    ► -4x =5y -20

    ►4x+5y-20 =0

    process 2:

    x intercept is 5 and y intercept is 4​

    so,the equation , \frac{x}{5}+\frac{y}{4} = 1

    \frac{4x+5y}{20} =1

    4x+5y -20 =0

    0
    2021-08-13T12:05:30+00:00

    Answer:

    Since the x intercept of the line is 4 and it’s y intercept is -3 the intercept form of the eqn.of the line is x/a + y/b = 1 where a,b are it’s x intercept and y intercept respectively.

    So eqn.of the line is x/4 + y/(-3) = 1

    × by 12 we get 3x – 4y = 12

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