Find the equation to the locus of the point which is equidistant from the coordinate axes. [Ans: [tex]x ^{2} – {y}^{2} = 0[/te Question Find the equation to the locus of the point which is equidistant from the coordinate axes.[Ans: ]Need the Explanation to this question.. in progress 0 Math Allison 1 month 2021-08-23T05:34:32+00:00 2021-08-23T05:34:32+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Let P(h,k) be any point in the locus.

Let PM be the perpendicular distance of P fro x-axis, i.e.,

PM=∣x∣

Let PNeft be the perpendicular distance of P fro y-axis, i.e.,

PN=∣y∣

∵PM=PN(Given)

⇒∣x∣=∣y∣

Squaring both sides, we have

x

2

=y

2

⇒x

2

−y

2

=0.

Thus, locus of P is x

2

−y

2

=0.