Find the equation to the locus of the point which is equidistant from the coordinate axes. [Ans: [tex]x ^{2} – {y}^{2} = 0[/te

Question

Find the equation to the locus of the point which is equidistant from the coordinate axes.
[Ans:
x ^{2}  -  {y}^{2}  = 0
]
Need the Explanation to this question..​

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Allison 1 month 2021-08-23T05:34:32+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-23T05:36:31+00:00

    Answer:

    Let P(h,k) be any point in the locus.

    Let PM be the perpendicular distance of P fro x-axis, i.e.,

    PM=∣x∣

    Let PNeft be the perpendicular distance of P fro y-axis, i.e.,

    PN=∣y∣

    ∵PM=PN(Given)

    ⇒∣x∣=∣y∣

    Squaring both sides, we have

    x

    2

    =y

    2

    ⇒x

    2

    −y

    2

    =0.

    Thus, locus of P is x

    2

    −y

    2

    =0.

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