Find the equations of the tangent and normal to the given curves at the indicated points: y = x⁴ – 6x³ + 13x²– 10x + 5 at (1, 3)

Question

Find the equations of the tangent and normal to the given curves at the indicated points:
y = x⁴ – 6x³ + 13x²– 10x + 5 at (1, 3)

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Ximena 2 weeks 2021-10-04T02:16:18+00:00 2 Answers 0 views 0

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    0
    2021-10-04T02:17:42+00:00

    Answer:

    Hope this helps !!! 🙂

    Step-by-step explanation:

    0
    2021-10-04T02:18:10+00:00

    Two lines are perpendicular iff (if and only if) the product of their gradients is -1. Therefore to work out the gradient of a normal you have to find the gradient of the tangent. The gradient of the normal will be −1gradientoftangent

    The gradient of a tangent at the point (x,y(x)) is the derivative of y(x) at x.

    let f(x) be the gradient of the normal at the point x.

    f(x)=−1ddx(2×2–3x)=−14x−3

    Edit: Has someone changed the question, because when I answered the question it was “what is the gradient of the normals of the curve 2x^2–3x” (or something similar to

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