find the Greatest number which divides 615 and 963 ,leaving Reminder 6 in each Case .​

Question

find the Greatest number which divides 615 and 963 ,leaving Reminder 6 in each Case .​

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Kinsley 1 month 2021-10-22T00:27:41+00:00 2 Answers 0 views 0

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    0
    2021-10-22T00:28:41+00:00

    Answer:

    In this question, since remainder is six, so we will subtract 6 from 615 and 963 i.e. 609 and 957. Then, we will find the H.C.F. of 609 and 957, that is going to be our answer.

    957= 3×11×29

    609= 3×3×29

    So, H.C.F.= 3×29= 87

    hope it will help you

    0
    2021-10-22T00:28:54+00:00

    To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

    Consider HCF be x.

    In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

    609 = 3 x 3 x 29

    957= 3 x 11 x 29

    ⇒ x = 3 x 29 = 87

    ∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

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