Find the greatest possible number which can divide 76, 132 and 160 and leaves remainder same in each case

Question

Find the greatest possible number which can divide 76, 132 and 160 and leaves remainder same in each case

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Melanie 1 month 2021-08-17T08:19:32+00:00 1 Answer 0 views 0

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    2021-08-17T08:21:22+00:00

    Answer:

    4

    Step-by-step explanation:

    when you divide by 4 these no then we found 0 is a remainder in each casses.

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18:9+8+9*3-7:3-1*13 = ? ( )