Find the number of solutions for the equation: x + y + z = 2002 where x, y, z ∈ N.

Question

Find the number of solutions for the equation: x + y + z = 2002 where x, y, z ∈ N.

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Eliza 2 weeks 2021-09-09T04:28:52+00:00 1 Answer 0 views 0

Answers ( )

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    2021-09-09T04:30:50+00:00

    Answer:

    x+y+z+=2002

    Step-by-step explanation:

    ×,y,z,€N

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