Find the numerical value of the following expression, where A+B=90°. sec2A−cot2Bcsc2B−tan2A+2sin2Asec2B−3(cos2A+cos2B)

Question

Find the numerical value of the following expression, where A+B=90°. sec2A−cot2Bcsc2B−tan2A+2sin2Asec2B−3(cos2A+cos2B)

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Clara 1 month 2021-08-16T19:39:46+00:00 1 Answer 0 views 0

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    2021-08-16T19:40:49+00:00

    Answer:

    sec^2A + sec^2B= sec^2Asec^2B

    sec^2(90-B) + sec^2B

    cosec^2B + sec^2B

    1/sin^2B + 1/cos^2B

    sin^2B+cos^2B/sin^2Bcos^2B

    1/ssin^2Bcos^2B

    sec^2Bcosec^2B

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