Find the perimeter of a rectangle whose area=8/2/3. Square mm length=5/7/9mm

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Find the perimeter of a rectangle whose area=8/2/3. Square mm length=5/7/9mm

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Samantha 1 month 2021-08-18T16:11:01+00:00 1 Answer 0 views 0

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    2021-08-18T16:12:21+00:00

    Answer:

    Step-by-step explanation:

    the perimeter of rectangle = 2×(l+b)

    the area of rectangle= 8/2/3=24/3

    length=45/7

    so, 24/3=2×45/7+b

    b=-17

    perimeter = 2×l+b

    =2×45/7+(-17)

    =56/7

    = 8mm Ans____

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