Find the smallest no which divides40 and leaves 7 in each case

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Find the smallest no which divides40 and leaves 7 in each case

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Claire 1 month 2021-08-16T14:39:57+00:00 1 Answer 0 views 0

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    2021-08-16T14:41:01+00:00

    Answer:

    This number leaves remainder 7 when divided by those 3 number. Hence 127 is the smallest number that leaves 7 as remainder which divided by those numbers.

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18:9+8+9*3-7:3-1*13 = ? ( )