Find the smallest number which when decreased by 3 is completely divisible by 18,27,32 and 36 Question Find the smallest number which when decreased by 3 is completely divisible by 18,27,32 and 36 in progress 0 Math Raelynn 1 month 2021-08-17T08:09:24+00:00 2021-08-17T08:09:24+00:00 2 Answers 0 views 0

## Answers ( )

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Answer:867

Step-by-step explanation:L.C.M. of 18, 36, 32 and 27

= 2 × 2 × 3 × 3 × 3 × 8 = 864

∴ required number = 864 + 3 = 867

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