Find the smallest number which when decreased by 3 is completely divisible by 18,27,32 and 36​

Question

Find the smallest number which when decreased by 3 is completely divisible by 18,27,32 and 36​

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Raelynn 1 month 2021-08-17T08:09:24+00:00 2 Answers 0 views 0

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    2021-08-17T08:11:19+00:00

    I hope this thishelps! !!!

    0
    2021-08-17T08:11:20+00:00

    Answer:

    867

    Step-by-step explanation:

    L.C.M. of 18, 36, 32 and 27

    = 2 × 2 × 3 × 3 × 3 × 8 = 864

    ∴ required number = 864 + 3 = 867

    please mark my answer brainliest…..

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