Find the smallest number which when divided by 32, 72 and 80 leaves remainder 14 in each case

Question

Find the smallest number which when divided by 32, 72 and 80 leaves remainder 14 in each case

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Isabella 3 weeks 2021-10-04T01:54:37+00:00 1 Answer 0 views 0

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    2021-10-04T01:56:23+00:00

    Answer:

    1454

    Step-by-step explanation:

    L. C. M of 32,72,80= 2×2×2×2×2×9×5

    = 1440

    It leaves remainder 14 in each case

    then 1440+14 = 1454

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