Find the square of the following using the identity ( a+b)=a2+2ab+b2.a)99

Question

Find the square of the following using the identity ( a+b)=a2+2ab+b2.a)99

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Vivian 2 weeks 2021-10-07T12:36:34+00:00 2 Answers 0 views 0

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    0
    2021-10-07T12:38:12+00:00

    Answer:

    the square of 99 is 10201

    Step-by-step explanation:

    99 = 100-1

    99^{2}=(100-1)^{2}\\

    \\(100-1)^{2} = (100)^{2}+2*(100)*(1)\\\\=10000+201+1\\\\=10201\\

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    0
    2021-10-07T12:38:23+00:00

     {99}^{2}

     = ( {100 - 1})^{2}

     = (100) ^{2}  - 2( 100)(1) +  {(1)}^{2}

    using \: identity \:  (a  -  b )^{2}  =  {a}^{2}  - 2ab +  {b}^{2}

     = 10000 - 200 + 1

     = 9801

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