find the sum of first 8 multiples of 3 (chapter AP) ​

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find the sum of first 8 multiples of 3 (chapter AP)

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Nevaeh 2 weeks 2021-09-09T18:01:10+00:00 2 Answers 0 views 0

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    0
    2021-09-09T18:02:57+00:00

    plzz hit thank n follow if it helps

    Step-by-step explanation:

    first multiple of 3 (a)= 3

    common difference (d)= 3

    no of terms (n) =8

    sum of terms = n/2 ( 2a+ ( n-1)d)

    = 4[ 2×3 + 7×3]

    =4[ 6 + 21]

    = 4× 27

    = 108

    0
    2021-09-09T18:03:03+00:00

    Answer:

    3 +6+9+12+15+18+21+24 —

    Step-by-step explanation:

    108

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18:9+8+9*3-7:3-1*13 = ? ( )