Find the sum of first 8 terms of AP whose first term is 3 and common difference is 6.​

Question

Find the sum of first 8 terms of AP whose first term is 3 and common difference is 6.​

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Caroline 1 month 2021-08-14T12:53:54+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-14T12:54:58+00:00

    here is ur ans …

    n = 8

    d = 6

    a = 3

    so..

    Sn = n/2 [2a + (n -1 ) * d ]

    : S8 = 8/2 [ 2*3 + ( 8 1 ) * 6 ]

    : S8 = 4 [ 6 + 7*6 ]

    : S8 = 4 [ 6 + 42 ]

    : S8 = 4 * 48

    therefore ..

    S8 = 192

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    0
    2021-08-14T12:54:59+00:00

    Answer:

    Given:

    a=3, d=6

    Sn=n/2(2a+(n-1)d)

    S8=4(6+42)

    S8=198

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