Find the value of 125p^3-8q^3 if 5p-2q=1 and pq=2?

Question

Find the value of 125p^3-8q^3 if 5p-2q=1 and pq=2?

in progress 0
Harper 2 weeks 2021-10-07T13:08:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-07T13:09:33+00:00

    If we assume p=1 and q=2

    Then,

    5p2q=1

    => 5×12×2=1

    => 54=1

    => 1=1

    125p³-8q³

    = (5p)³-(2q)³

    = (5p-2q){(5p)²+5p×2q+(2q)²}

    = 1 × (25p²+10pq + 4q²)

    = 25p²+4q²+10×2

    = 25p²+4q²+20

    = 25 ×1×1+4×2×2+20

    = 25+16+20

    = 61

    Hope it helps you.....

    please mark my answer as brainleist.......

    0
    2021-10-07T13:09:35+00:00

    Answer:

    185436-₹5;₹57789964

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )