find the value of angle AOB of circle in which exterior part is of 35degree Question find the value of angle AOB of circle in which exterior part is of 35degree in progress 0 Math Lyla 1 month 2021-08-13T01:42:49+00:00 2021-08-13T01:42:49+00:00 2 Answers 0 views 0

## Answers ( )

Answer:325 degree “

360-35=ans

Answer:∠APB = 50°

By degree measure theorem

∠AOB = 2∠APB

⇒ ∠APB = 2 × 50° = 100° since OA = OB [Radius of circle]

Then ∠OAB = ∠OBA [Angles opposite toequalsides]

Let ∠OAB = x

In ΔOAB, by angle sum property

∠OAB + ∠OBA + ∠AOB = 180°

⟹ x + x + 100° = 180°

⟹ 2x = 180° – 100°

⟹ 2x = 80°

⟹ x = 40°

∠OAB = ∠OBA = 40°

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