find the value of angle AOB of circle in which exterior part is of 35degree​

Question

find the value of angle AOB of circle in which exterior part is of 35degree​

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Lyla 1 month 2021-08-13T01:42:49+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T01:43:57+00:00

    Answer:

    325 degree “

    360-35=ans

    0
    2021-08-13T01:44:48+00:00

    Answer:

    ∠APB = 50°

    By degree measure theorem

    ∠AOB = 2∠APB

    ⇒ ∠APB = 2 × 50° = 100° since OA = OB [Radius of circle]

    Then ∠OAB = ∠OBA [Angles opposite toequalsides]

    Let ∠OAB = x

    In ΔOAB, by angle sum property

    ∠OAB + ∠OBA + ∠AOB = 180°

    ⟹ x + x + 100° = 180°

    ⟹ 2x = 180° – 100°

    ⟹ 2x = 80°

    ⟹ x = 40°

    ∠OAB = ∠OBA = 40°

    Step-by-step explanation:

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