find the value of k,if x-2 is a factor of p (x)=x2+2kx+8.

Question

find the value of k,if x-2 is a factor of p (x)=x2+2kx+8.

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Bella 1 month 2021-08-17T06:08:33+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-17T06:09:43+00:00

    Equating the function to 0 we get,

    p(x) = 0

    => x²+2kx+8 = 0 —– (1)

    ∵ x-2 is a factor of p(x)

    ∴ one of the roots of (1) is 2

    Putting x = 2 in (1) we get,

    (2)²+2k(2)+8 = 0

    => 4+4k+8 = 0

    => 4k+12 = 0

    => 4k = -12

    => k = -3

    0
    2021-08-17T06:09:44+00:00

    Step-by-step explanation:

    Let p (x)=x2+2kx+8.

    if x-2 is factor

    then,

    p(2)=0

    p(2)=2×2+2kx2+8=0

    4k+12=0

    k= -3

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