find the value of k if: xy²k=(4xy+3y)² -(4xy-3y)²​

Question

find the value of k if: xy²k=(4xy+3y)² -(4xy-3y)²​

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Sarah 2 months 2021-10-10T18:58:53+00:00 1 Answer 0 views 0

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    2021-10-10T19:00:00+00:00

    Answer:

    x {y}^{2} k =  {(4xy + 3y)}^{2}  -  {(4xy - 3y)}^{2} \\    x {y}^{2} k = (4xy + 3y - 4xy + 3y)(4xy + 3y + 4xy - 3y) \\ x {y}^{2} k = 6y \times 8xy \\  = 48x {y}^{2}  \\ then \: \\  k =  \frac{48x {y}^{2} }{xy {}^{2} }  \\  = 48

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