Find the zeroes of the quadratic polynomial 3x²–2 and verify the relationship between the zeroes and the coefficients.​

Question

Find the zeroes of the quadratic polynomial 3x²–2 and verify the relationship between
the zeroes and the coefficients.​

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Eden 1 month 2021-09-14T22:28:24+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-14T22:29:34+00:00

    Answer:

    3x²-2=0

    3x²=2

    x=√2/3

    x= -2/3 or 2/3

    ∝= √-2/3

    β= √2/3

    Sum of zeroes= -b/a

    ∝+β                 =  0/3

    √-2/3+2/3          =0

    √-2+2/3              =0

    √0/3                  =0

    0=0

    product of zeroes=c/a

    ∝×β                       = -2/3

    √-2/3×√2/3          = -2/3

    √-4/9                    = -2/3

    -2/3                       = -2/3

    0
    2021-09-14T22:29:41+00:00

    Answer:

    3x^2-2 is the given quadratic polynomial

    To get zeroes of the polynomial we should equate to ‘zero 0’

    3x^2-2=0

    3x^2=2

    x^2=2/3

    x=root of (2/3) (OR) -root of(2/3)

    Step-by-step explanation:

    VERIFICATION :-

    The relatin between zeroes and coefficients is

    (i) Sum of zeroes=-(coefficient of x)/(coefficient of x^2)

    Root (2/3)-root (2/3)=-0/3

    0=0

    (ii) Product of zeroes = constant / (coefficient of x^2)

    Root of(2/3)×-root of(2/3)=-2/3

    -[root of (2/3)]^2=-2/3

    -2/3=-2/3

    Hence verified

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