Find the zeroes of the quadratic polynomial 6x² + x-2 and verify The relationship between the Zeroes and the coefficient

Question

Find
the zeroes of the quadratic
polynomial 6x² + x-2 and verify
The relationship between the Zeroes
and the coefficients.​

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Kylie 1 month 2021-08-14T01:03:35+00:00 1 Answer 0 views 0

Answers ( )

    0
    2021-08-14T01:05:09+00:00

    Answer:

    6 {x}^{2}  + x - 2 = 0 \\  \\ 6 {x}^{2}  + 4x - 3x - 2 = 0 \\  \\ 2x(3x + 2) - 1(3x + 2) = 0 \\  \\ (3x + 2) \:  \: (2x - 1) = 0

    If 3x + 2 = 0

    3x =  - 2 \\  \\ x =  \frac{ - 2}{3}

    If 2x – 1 = 0

    2x = 1 \\  \\ x =  \frac{1}{2}

    Now,

    sum \: of \: zeroes( \alpha  +  \beta ) =  \frac{ -2 }{3}  +  \frac{1}{2}  \\  \\  =  \frac{ - 4 + 3}{ 6}  \\  \\  =  \frac{ - 1}{6}  =  \frac{ - b}{a}

    product \: of \: zeroes( \alpha  \beta ) =  \frac{ - 2}{3}  \times  \frac{1}{2}  \\  \\  =  \frac{ - 1}{3}  =  \frac{c}{a}

    If you satisfied mark it brainliest.

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