first term and common difference of an A.P are 6 and 3 respectively ;find S27​

Question

first term and common difference of an A.P are 6 and 3 respectively ;find S27​

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Adalyn 4 weeks 2021-11-03T19:22:49+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-11-03T19:24:12+00:00

    Answer:1188

    Step-by-step explanation: a=6, d=3,n=27

                                                 sn=n/2[2a+(n-1)d]

    s27=27/2[2(6)+(27-1)3]

          =13.2[12+ 78]

           =13.2[90]

           =1188

        therefore, the answer is 1188

                                               

    0
    2021-11-03T19:24:37+00:00

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    Answer in 2 methods:

    1st method:

    since ,a=6 , d=3

    we need to find S27=?

    HERE, Sn=n/2{2a+{n-1}d}

                   =27/2{2×6+{27-1}3}

                   =27/2{12+26×3}

                   =27/2{90}

                   =27×45

                    =1215

    hence sum to 27 terms is 1215

    2nd method:

    Given

    a=6

    n=27

    d=3

    S27=?

    n=27

    SOLUTION

    S27=(n/2){2a+(n-1)d}

    =(27/2){2(6)+(27-1)(3)}

    =(27/2){12+26×3}

    =(27/2)(12+78)

    =(27/2)(90)

    =13.5×90

    =1215

    ANSWER: Sn=1215

    Step-by-step explanation:

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