for what value of k quadratic equation kn 2 – kn+1 = o has equal roots​

Question

for what value of
k quadratic equation
kn 2 – kn+1 = o has equal
roots​

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Gianna 4 weeks 2021-08-16T15:27:16+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-16T15:28:29+00:00

    For k = 4, the given quadratic equation has equal roots.

    Step-by-step explanation:

    The quadratic equation is kx^2-kx+1=0kn²−kn+1=0

    on Comparing with ax²+bx+c=0

    ax²+bx+c=0

    a = k, b = -k, c = 1

    Now, for the equal roots, we have,

    b²-4ac=0

    k²-4k=0

    k(k-4)=0

    k=4

    Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0

    Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0Therefore, for k = 4, the given quadratic equation has equal roots.

    .

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    .

    itzDopeGirl❣

    0
    2021-08-16T15:28:57+00:00

    Answer:

    For k = 4, the given quadratic equation has equal roots.

    Step-by-step explanation:

    The quadratic equation is kx^2-kx+1=0kn²−kn+1=0

    on Comparing with ax²+bx+c=0

    ax²+bx+c=0

    a = k, b = -k, c = 1

    Now, for the equal roots, we have

    b {}^{2}  - 4ac = 0 \\ k {}^{2}  - 4 \times k = 0 \\ k {}^{2}  - 4k = 0 \\ k(k - 4) = 0 \\ k = 0 \\ k = 4

    Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0

    Therefore, for k = 4, the given quadratic equation has equal roots.

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