Four years ago, a mother was four times as old as her daughter. Six years later, the mother will be two and a half times as old as her daugh

Question

Four years ago, a mother was four times as old as her daughter. Six years later, the mother will be two and a half times as old as her daughter at that time. Find the present ages of mother and herdaughter.​

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Ximena 1 month 2021-10-27T01:43:09+00:00 1 Answer 0 views 0

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    2021-10-27T01:44:14+00:00

    let mother’s age be y years and his daughter’s age be x years

    ATP

    four years ago x-4=4(y-4)

    divide by 4 x-1=y-4

    x=y-4+1

    x=y-3 —————————(1)

    six years later x+6=2.5 (y+6)

    x + 6 = 2.5y + 15

    x = 2.5y + 15 - 6

    x = 2.5y + 9 -  -  -  -  -  - (2)

    by 1 and 2

    y - 3 = 2.5y + 9

    y - 2.5y = 9 + 3

    1.5y = 12

    y =  \frac{12}{1.5}  =  \frac{12 \times 10}{15}

    y = 8

    put y in equation 1

    x=y-3=8-3=5

    •°•mother’s age is 8 years and daughter’s age is 5 years

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