Given a sequence of integers between 20 and 300 which are divisible by 9.Find their sum.

Question

Given a sequence of integers between 20 and 300 which are divisible by 9.Find their sum.

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Allison 1 month 2021-08-14T18:29:57+00:00 1 Answer 0 views 0

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    2021-08-14T18:31:10+00:00

    Answer:

    Required sequence=27,36,45……..396.

    Let the no of terms be ‘n’.

    27+(n-1)9=396

    (n-1)9=396-27

    n-1=369/9

    n=41+1=42

    Sum= 42/2(27+396)

    =21×423=8883

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