Given x + y = 11 and xy = 20 , Find the value of: (x – y)^2

Question

Given x + y = 11 and xy = 20 , Find the value of: (x – y)^2

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Eva 2 weeks 2021-11-22T00:32:20+00:00 2 Answers 0 views 0

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    0
    2021-11-22T00:33:46+00:00

    Answer:

    (x-y)²2

    =(x²+y²-2xy)2

    ={(x+y)²-2xy-2xy}2

    ={(x+y)²-4xy}2

    ={(11)²-4×20}2

    =(121-80)2

    =2×41

    =82

    Step-by-step explanation:

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    0
    2021-11-22T00:34:15+00:00

    Answer:

    (x+y)^2=11^2

    x^2+y^2+2ky=121

    x^2+y^2+4=121

    x^2+y^2=117

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