Half the perimeter of a rectangular garden, whose length is 4 m more than its wid 36 m. Find the dimensions of the garden.​

Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its wid
36 m. Find the dimensions of the garden.​

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Kaylee 3 weeks 2021-10-01T21:28:39+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-10-01T21:30:08+00:00

    Step-by-step explanation:

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    • It is given that, half of the Perimeter of reactangular garden is 36 :]

    So,

    ➦ 2(l + b)/2 = 36

    ➦ l + b = 36…….[Equation (i)]

    Now,

    • Let width be x
    • and length be x + 4

    Putting this values in equation (i) we get,

    ➝ l + b = 36

    ➝ x + x + 4 = 36

    ➝ 2x + 4 = 36

    ➝ 2x = 36 – 4

    ➝ 2x = 32

    ➝ x = 32/2

    x = 16 m

    Therefore,

    • Width of reactangular garden = x = 16 m
    • Length of the reactangular garden = x + 4 = 16 + 4 = 20 m

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    0
    2021-10-01T21:30:10+00:00

    Answer:

    The dimensions of the rectangular garden are 20 m and 16 m.

    Step-by-step explanation:

    Given :

    • Half the perimeter of a rectangular garden, whose length is 4 m more than its width is 36 m.

    To find :

    • The dimensions of the garden.

    Solution :

    Let the width of the rectangular garden be x m.

    The length of the rectangular garden is 4 more than its width.

    Then,

    • Length = (x+4) m

    According to the question,

    2(x+4+x)/2 = 36

    → x+4+x = 36

    → 2x+4 = 36

    → 2x = 36-4

    → 2x = 32

    → x = 32/2

    → x = 16

    • Width of the rectangular garden = 16 m

    Then,

    • Length of the rectangular garden = (16+4) = 20 m

    __________________

    Additional information :

    • Area of rectangle = length × breadth
    • Diagonal of rectangle =√(length ² + breadth ²)
    • Area of square = side ²
    • Perimeter of square = 4×side.

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