## Half the perimeter of a rectangular garden, whose length is 4 m more than its wid 36 m. Find the dimensions of the garden.​

Question

Half the perimeter of a rectangular garden, whose length is 4 m more than its wid
36 m. Find the dimensions of the garden.​

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3 weeks 2021-10-01T21:28:39+00:00 2 Answers 0 views 0

1. Step-by-step explanation: • It is given that, half of the Perimeter of reactangular garden is 36 :]

So,

➦ 2(l + b)/2 = 36

➦ l + b = 36…….[Equation (i)]

Now,

• Let width be x
• and length be x + 4

Putting this values in equation (i) we get,

➝ l + b = 36

➝ x + x + 4 = 36

➝ 2x + 4 = 36

➝ 2x = 36 – 4

➝ 2x = 32

➝ x = 32/2

x = 16 m

Therefore,

• Width of reactangular garden = x = 16 m
• Length of the reactangular garden = x + 4 = 16 + 4 = 20 m The dimensions of the rectangular garden are 20 m and 16 m.

Step-by-step explanation:

Given :

• Half the perimeter of a rectangular garden, whose length is 4 m more than its width is 36 m.

To find :

• The dimensions of the garden.

Solution :

Let the width of the rectangular garden be x m.

The length of the rectangular garden is 4 more than its width.

Then,

• Length = (x+4) m

According to the question,

2(x+4+x)/2 = 36

→ x+4+x = 36

→ 2x+4 = 36

→ 2x = 36-4

→ 2x = 32

→ x = 32/2

→ x = 16

• Width of the rectangular garden = 16 m

Then,

• Length of the rectangular garden = (16+4) = 20 m