Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs h

Question

Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 2 meters of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36660. How much trouser material did he buy?

pls answer it is urgent​
pls answer by step by step explanation.

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Iris 2 weeks 2021-09-14T07:45:01+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-14T07:46:16+00:00

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    Equations with linear expressions in one variable only are known as linear equations in one variable.

    An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).

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    Solution:

    Let Hasan bought 2x m of trouser material and 3x m of the shirt material.

    Per metre selling price(S.P) of the trouser material = ₹90+90×12/100

    = 90 + 1.2× 9

    = 90 + 10.8

    =₹100.80

    Per metre selling price(S.P) of trouser of shirt material

    = ₹50+ 50× 10/100

    = ₹ 50 + 5

    =₹55

    Given: total amount of sale= ₹ 36660

    100.80 x (2x) + 55 x (3x) = ₹36660

    201.60 x + 165x = 36660

    366.60 x = 36660

    X= 36660/366.60

    x = 100

    Trouser material = 2x m = (2×100)m = 200m.

    Hasan bought 200 m of trouser material.

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    0
    2021-09-14T07:46:45+00:00

    Step-by-step explanation:

    Equations with linear expressions in one variable only are known as linear equations in one variable.

    An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).

    ==========================================================

    Solution:

    Let Hasan bought 2x m of trouser material and 3x m of the shirt material.

    Per metre selling price(S.P) of the trouser material = ₹90+90×12/100

    = 90 + 1.2× 9

    = 90 + 10.8

    =₹100.80

    Per metre selling price(S.P) of trouser of shirt material

    = ₹50+ 50× 10/100

    = ₹ 50 + 5

    =₹55

    Given: total amount of sale= ₹ 36660

    100.80 x (2x) + 55 x (3x) = ₹36660

    201.60 x + 165x = 36660

    366.60 x = 36660

    X= 36660/366.60

    x = 100

    Trouser material = 2x m = (2×100)m = 200m.

    Hasan bought 200 m of trouser material.

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