How many 3-digits even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?​

Question

How many 3-digits even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?​

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Kaylee 1 month 2021-08-16T17:18:46+00:00 2 Answers 0 views 0

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    0
    2021-08-16T17:20:19+00:00

    Answer:

    ➡️Let the 3-digit number be ABC, where C is at the unit’s place, B at the tens place and A at the hundreds place.

    ➡️As the number has to even, the digits possible at C are 2 or 4 or 6.

    ➡️That is number of possible digits at C is 3.

    ➡️Now, as the repetition is allowed, the digits possible at B is 6.

    ➡️Similarly, at A, also, the number of digits possible is 6.

    ➡️Therefore,

    ➡️ The total number possible 3 digit numbers = 6 × 6 × 3 = 108.

    Step-by-step explanation:

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    0
    2021-08-16T17:20:39+00:00

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    How many 3-digits even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

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    ➡️Let the 3-digit number be ABC, where C is at the unit’s place, B at the tens place and A at the hundreds place.

    ➡️As the number has to even, the digits possible at C are 2 or 4 or 6.

    ➡️That is number of possible digits at C is 3.

    ➡️Now, as the repetition is allowed, the digits possible at B is 6.

    ➡️Similarly, at A, also, the number of digits possible is 6.

    ➡️Therefore,

    ➡️ The total number possible 3 digit numbers = 6 × 6 × 3 = 108.

    \Large\mathcal\green{FOLLOW \: ME}

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