How many different ways are there to pain ‘n’ balls with 4 colors ( A, B, C, D). The number of balls in color A must be odd. The number of b

Question

How many different ways are there to pain ‘n’ balls with 4 colors ( A, B, C, D). The number of balls in color A must be odd. The number of balls in color B must be even. (includes 0)

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Melody 1 month 2021-08-12T17:39:27+00:00 2 Answers 0 views 0

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    0
    2021-08-12T17:40:34+00:00

    Answer:

    mark brainliest please

    Step-by-step explanation:

    got em annadu you want it now I am going to do the work of 88h I was in bed all weekend long to

    0
    2021-08-12T17:40:54+00:00

    Answer:

    This is known as the coupon collector’s problem.

    The average number of tries needed to see each of 4 colors is

    44+43+42+41=813

    The terms are 4/4 for the time to take one ball; then 4/3 for the average time it takes after the first ball until you see another code; 4/2 for the average time it takes after the first time you see the second color until you see a third, and finally 4/1 for the time you then have to wait until you see the last color. (These can just be added due to the additivity of expectations).

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