how many terms of an ap 3 5 7 9 dotdotdot must be added to get the sum 120​

Question

how many terms of an ap 3 5 7 9 dotdotdot must be added to get the sum 120​

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Caroline 1 month 2021-08-18T07:33:43+00:00 1 Answer 0 views 0

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    2021-08-18T07:34:53+00:00

    Answer:

    Let the number of terms be ‘n’.

    A/q. n/2(2×3+(n-1)2)=120

    n(3+n-1)=120

    n^2+2n-120=0

    n^2+12n-10n-120=0

    n(n+12)-10(n+12)=0

    (n+12)(n-10)=0

    n+12 =0 or n-10=0

    n=(-12.) or n=10

    Required no of terms=10 terms

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